Question

:) Find the value of k for which the quadratic equation 4 y2 – 3ky + 1 = 0
has equal roots.
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Answer 1

Step-by-step explanation:

4y² - 3ky + 1 = 0

for equal roots, D = 0

a = 4, b = - 3k and c = 1

D = (-3k)² - 4×4×1 = 0

D = 9k² - 16 = 0

=> k² = 16/9

=> k = √(16/9)

=> k = ± 4/3