Question

Find the value of k for which the Quadratic equation 4x4 - 2 (k+1)x + (k+1) was equal roots​

Answer 1

Answer:

k=3,(-1)

Step-by-step explanation:

Discriminant for equal roots => b²-4ac=0

a=4,b= 2(k+1) , c=(k+1)

4(k+1)²-4(4)(k+1)=0

4(k²+2k+1)-16k-16=0

4k²+8k+4-16k-16=0

4k²-8k-12=0

4(k²-2k-3)=0

k²-2k-3=0

k²+k-3k-3=0

k(k+1)-3(k+1)=0

(k-3)(k+1)=0

k=3,(-1)