Question

Find the value of k for which the quadratic equation 9x^2-3k^2+k=0 has equal roots​

Answer 1

Answer:

to have equal roots

discriminant should be equal to zero

D =0

b^2 - 4ac = 0

-(4)(9)(-3k^2+k) = 0

(-36)( -3k^2+k) =0

-3k^2= -k

k^2 = k/3

k=1/3