Question

Find the value of k for which the quadratic equation 9x^2 - 3kx + K = 0 has equal roots.

Answer 1

Hey there!!


▶Q:- Find the value of k for which the quadratic equation 9x² - 3kx + K = 0 has equal roots.


▶ Solution :-

The given equation is 9x² - 3kx + k = 0.

This is of the form ax² + bx + c = 0,

where a = 9, b = - 3k and c = k .


Then, the discriminant (D) is :-

•°• D = ( b² - 4ac ) .

= ( -3k )² - 4 × 9 × k.

= 9k² - 36k.


Since, the given equation has equal roots, we have

°•° D = 0.

=> 9k² - 36k = 0.

=> 9k( k - 4 ) = 0.

=> k - 4 = 0/9k .

=> k - 4 = 0.

•°• k = 4 .


✔✔ Hence, the required value of k is 4 ✅✅.

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THANKS



#BeBrainly.

Answer 2

Heya user..!!

Here is ur answer..!!

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Answer:

9x²-3kx₊k = 0

By quadratic formula :

a = 9,  b = -3k , c = k

b²-4ac =  ( -3k ) ² - 4 ( 9) (k)

            =  9k²- 36k = 0

           = k²-4k=0

          = k ( k - 4 ) = 0

           = k = 0 or k = 4

Hence :

       ∴       k=4      

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I Hope this may help u..!!

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