Question

find the value of k for which the quadratic equation has real root. 1) 2x^2 + kx + 3=0
​

Answer 1

Answer:

for the equation having real root then b^2_4ac=0

Step-by-step explanation:

2x^2+k×+3=0

here a=2,b=k,c=3

b^2_4ac=0

k^2_4×2×3=0

k^2_24=0

k^2=24

k=square root of 24