Find the value of 'k' for which the quadratic equation
(k+1)x - 6(k+1)x+ 3(k+9) = 0, k
1
has equal roots.
Answers
Answered by
0
Answer:
2
Step-by-step explanation:
36(k+1)² -12 (k+1)(k+9) = 0
k ≠ -1
3k+3 = k+9
k = 2
Answered by
0
Answer:
The value of k for which the roots are real and equal of the following equation 9x^2 - 24x + k = 0 is k = 16.
Step-by-step explanation:
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