Question

find the value of k for which the quadratic equation (k-2)x2+(2k-3)x+(5k-6)=0 has real roots
{3 marks}​

Answer 1

2k-4+2k-3(5k-6)=0

2k-4+2k-3(5k)-2k-3(6)=0

2k-4+20k-15k-12k-18=0

22k-27k-22=0

-5k=-22

k=22÷5

k=4.4