Question

Find the value of K for which the quadratic
equation (K-2)x²+(2k-3)x+(5k-6)=0 has
equal
roots.​

Answer 1

Since the above equation has equal roots

Hence

B

2

−4AC=0

Hence

4(2k−3)

2

−4(5k−6)(k−2)=0

4k

2

−12k+9−(5k

2

−16k+12)=0

−k

2

+4k−3=0

Or

k

2

−4k+3=0

(k−3)(k−1)=0

Hence

k=3 and k=1.