Question

Find the value of k for which the quadratic equation (k^2x^2-2(2k-1)x+4=0 has real and equa lroots

Answer 1

Answer:

For real and equal roots, D=0

[2(2k-1)]^2-4.k^2.4 = 0

=> 4k^2 - 4k +1 - 4k^2 = 0

=> k = 1/4