Question

Find the value of k for which the quadratic equation k + 4 x square + 3 + 1 + 1 is has equal roots also

Answer 1

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:k=-5}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ \tt{ : \implies 4x^{2} + 5 +k= 0 }\\ \\ \red{ \underline \bold{To \: Find : }} \\ \tt{: \implies value \: of \: k = ?}$

• According to given question :

$\tt{ : \implies 4x^{2} +5 + k= 0} \\ \\ \tt{\circ \: a = 4} \\ \\ \tt{\circ \: b = 0}\\\\ \tt{\circ \:c =(5+k)}\\ \\ \bold{Discriminant \: = 0} \\ \\ \tt{: \rightarrow \: D \implies {b}^{2} - 4ac = 0 } \\ \\ \tt{: \implies {b}^{2} - 4ac = 0} \\ \\ \text{Putting \: the \: given \: values} \\ \tt{: \implies 0^{2} - 4\times4\times (5+k)= 0 } \\ \\ \tt{: \implies \: -16(5+k) = 0 } \\ \\ \tt{ : \implies \: 5+k = 0 } \\\\ \tt{: \implies k= -5} \\ \\ \green{\tt{: \therefore k = -5 }}$