Question

Find the value of k for which the quadratic
equation (k+4)x²+ (k+1)x+1 = 0 has equal roots Also find these roots​

Answer 1

Answer:

k=5,k=-3

explanation:-

a=k+4,b=k+1,c=1

D=0(given)

Using discriminant formula:-

D=b²-4ac

0=(k+1)²-4(k+4)(1)

=k²+1+2k-4k-16

=k²-2k-15

=k²-5k+3k-15

=k(k-5)+3(k-5)

0=(k-5)(k+3)

k-5=0 k+3=0

k=5. k=-3