Question

Find the value of K for which
the quadratic equation k²x²-2(k-1) x
+4=0 has two real equal roots​

Answer 1

Answer:

For two equal real roots D = 0

b^2 - 4ac = 0

(-2(k-1))^2 - 4k^2×4 = 0

4(k-1)^2 - 16k^2 = 0

(k-1)^2 - 4k^2 = 0

(k-1)^2 - (2k)^2=0

(k-1 +2k)(k-1 -2k) =0

(3k-1)((-k -1)=0

3k-1=0 gives k = 1/3

-k -1 =0 gives k= -1