Question

find the value of k for which the quadratic equation kx^2-5 kx+k=0 has real and equal roots. PLS FASTT

Answer 1

ANSWER :–

GIVEN :–

kx² - 5kx + k = 0

TO FIND :–

VALUE OF 'K'

SOLUTION :–

● FOR REAL AND EQUAL ROOTS —

DISCRIMINATE WILL BE ZERO.

=》 D = b² - 4ac

▪︎ Here a = k , b = - 5k and c = k

=》 D = 0

=》 b² - 4ac = 0

=》 (-5k)² - 4(k)(k) = 0

=》 25 k² - 16 k² = 0

=》 9 k² = 0

=》 k = 0