Question

Find the value of k for which the quadratic equation kx bracket x - 2 + 6 is equal to zero has equal roots

Answer 1

I think it may help you.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:k=0\:and\:6}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ \tt{ : \implies kx (x-2) + 6= 0 }\\ \\ \red{ \underline \bold{To \: Find : }} \\ \tt{: \implies value \: of \: k = ?}$

• According to given question :

$\tt{ : \implies kx^{2} -2kx + 6= 0} \\ \\ \tt{\circ \: a = k} \\ \\ \tt{\circ \: b = -2k}\\\\ \tt{\circ \:c = 6}\\ \\ \bold{Discriminant \: = 0} \\ \\ \tt{: \rightarrow \: D \implies {b}^{2} - 4ac = 0 } \\ \\ \tt{: \implies {b}^{2} - 4ac = 0} \\ \\ \text{Putting \: the \: given \: values} \\ \tt{: \implies (-2k)^{2} - 4\times k \times 6= 0 } \\ \\ \tt{: \implies \: 4{k}^{2} -24k= 0 } \\ \\ \tt{ : \implies \: 4({k}^{2} - 6k) = 0 } \\\\ \tt{: \implies k(k-6)=0} \\ \\ \tt{: \implies k= 0\:and\:6}\\ \\ \green{\tt{: \implies k = 0, 6 }}$