Question

Find the value of K for which the quadratic equation kx(x – 2) + 6 = 0 has two equal roots.​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

The given equation is kx (x – 2) + 6 = 0.

kx (x – 2) + 6 = 0

∴ kx2 – 2kx + 6 = 0

Here a = k, b = – 2k and c = 6.

Discriminant of the quadratic equation = D = b2 – 4ac = (–2k)2 – 4 × k × 6 = 4k2 – 24k

Roots of the given quadratic equation are equal.

∴ D = 0

⇒ 4k2 – 24k = 0

⇒ 4k(k – 6) = 0

⇒ k = 0 or k – 6 = 0

⇒ k = 0 or k = 6

∴k = 6 (∵ k ≠ 0)

Thus, the value of k is 6.