Question

find the value of k for which the quadratic equation kx(X - 2) + 6 equal to zero has two equal roots.
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Answer 1

Answer :

k = 0 or k = 6

Explanation:

Given quadratic equation:

kx(x-2)+6=0

=> kx²-2kx+6 = 0 compare

this with ax²+bx+c=0 , we get

a=k , b = -2k , c = 6

Now ,

discreminant (D)=0

[ since ,Roots are equal ]

=> b²-4ac=0

=> (-2k)²-4×k×6 = 0

=> 4k² - 24k = 0

=> 4k(k-6) = 0

=> 4k = 0 or k-6 = 0

=> k = 0 or k = 6

••••

Answer 2

Answer:

k=6

Step-by-step explanation:

Kx(X-2)+6= kx²-2kx+6

By relation in a quadratic equation when b²-4ac=0 it has equal roots

So (-2k)²-4(6)(k)

4k²-24k=0       ÷4

k²-6k=0            ÷k

k-6=0

k=6