Question

Find the value of k for which the quadratic equation kx(x-2)+6=0has two equal zeroes

Answer 1

this is your answer

If x=1

then k=6

Answer 2

$y {x}^{2} \times (x - 2) + 6 = 0$

factorise the equation and find value for (x).

if you can answer this you can find it.

your answer'll be k=6.