Question

Find the value of k for which the quadratic equation kx²+2x+1=0,has real and distinct root.

Answer 1

For real and distinct roots

$b {}^{2} - 4ac \: = 0$

$(2) {}^{2} - 4(k)(1) = 0$

$4 = 4k$

$k \: = 1$

$thanks$

Answer 2

Answer:

For real and distinct roots

b {}^{2} - 4ac \: = 0b2−4ac=0

(2) {}^{2} - 4(k)(1) = 0(2)2−4(k)(1)=0

4 = 4k4=4k

k \: = 1k=1