Math, asked by kitchu66, 9 months ago

Find the value of k for which the quadratic equation kx²(x-2)+6=0 has distinct roots.

Answers

Answered by jiyasharma77

1

Answer:

kx² ( x - 2) + 6 =0

kx² - 2kx + 6

b²- 4ac =0

(-2k)²- (4)(6k) =0

4k²= 24k

k = 6

this is your answer

Previous Question

Next Question

Similar questions

Math, 4 months ago

The sum of a positive number and its reciprocal is 26 5 Find the number? Select one: 30 5 o 15 7 14 is the m...

Geography, 4 months ago

Q- Physiography of Odisha...

English, 4 months ago

I---- the Cds yesterday a)returned b)have returned c)was returned...

Math, 9 months ago

factorize the expressions ( ab + 2a) + b + 2...

India Languages, 9 months ago

लता ----------- फलम् आनयति | 1.रमाम् 2.रमा 3.रमायै...

Math, 1 year ago

Wht is the number ? 1. The sum of two digitd is 8. The ratio of the two dihgits is 1:3. Ii. The produvt of the 2 digit of a number is 12. The quotient of two digits is 3...

Social Sciences, 1 year ago

Why are so many people fascinated by mysteries? What features might make one mystery more fascinating than an why are so many people fascinated by mysteries? What features might make one mystery more fascinating than another?

Business Studies, 1 year ago

Which types of transactions are likely to be fraudulent, given the demographics and transactional history of a particular customer?