Question

Find the value of k for which the quadratic equation x 2 − 12x + k = 0 has
two real equal roots

Answer 1

Answer:

According to question,

kx2+2x+k=0

As, roots are equal,

So, Discriminant, D=0

⟹22−4k2=0

⟹k2=1

Hence, k=−+1

Answer 2

Answer:

k = 36

Explanation :

x² - 12x + k = 0

D = b² - 4ac

D : Discriminant ( ∆ )

a = 1 ; b = -12 ; c = k

∆ = ( -12 )² - 4 ( 1 ) ( k )

∆ = 144 - 4k

4k = 144

k = 144 / 4

k = 36