Find the value of k for which the root of quadratic equation kx (X - 2 ) + 6 = 0 are equal
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for real and equal root we b2-4ac=0
so compare it with ax2+bx+c
we 4k2-24k=0
4k(k-6)=0
so
4k=0,
k=6
so two values of k is 0 and 6
so compare it with ax2+bx+c
we 4k2-24k=0
4k(k-6)=0
so
4k=0,
k=6
so two values of k is 0 and 6
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