Question

Find the value of k for which the roots are real and equal of equation:
(k+1)x2 +2(k + 3)x + (k+ 8) = 0​

Answer 1

Answer:

Step-by-step explanation:

WHEN ROOTS ARE EQUAL DELTA =0

b SQUARE-4AC=0

Answer 2

Step-by-step explanation:

2^2(k+3)^2-4(k+1)(k+8)=0

4k^2+12k+18-4(k^2+k+8k+8)=0

4k^2+12k+18-4k^2-36k-12=0

6-24k=0

24k=6

K=1/4