Question

Find the value of k for which the roots are real and equal for the equation 9x^2 – 24x + k = 0

Answer 1

D=b^2-4ac
0=576-36k
576=36k
k= 16

Answer 2

$since \: the \: roots \: are \: equal \: the \: discriminant \: \\ must \: be \: equal \: to \: zero \\ discriminant = {b}^{2} - 4ac \\ ( { - 24)}^{2} - 4 \times 9k = 0 \\ k = 24 \times 24 \div 4 \times 9 = 16 \\ hence \: k = 16$
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