Math, asked by munishjaswal4111, 1 year ago

Find the value of k for which the Roots are real and equal of quadratic equation kx²-5x+k =0

Answers

Answered by shiri31
9
Hope it helps......................
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Answered by 1996shivdalvi
3

kx^2 -5x + k = 0

a = k, b = -5, c = k

To have equal roots, b^2 - 4ac = 0

(-5)^2 - 4(k)(k) = 0

      25 - 4k^2 = 0

   5^2 - (2k)^2 = 0

(5 + 2k)(5 - 2k) = 0

   5     5

k = - , - -

   2     2

k = ±2.5


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