Question

Find the value of 'k', for which the roots of equation 4x² - 2(k+1)x + (k + 4) = 0 are real and
equal.(WITH SOLUTION)
(A) k = 3
(B) k> 3
(C) k = 5,-3
(D) k=-5​

Answer 1

Answer:

Step-by-step explanation:

b² - 4ac

(-2k -2)² - 4 (4)(k + 4)

4k² + 8k + 4  - 16k - 64 = 0

4k² - 8k - 60 = 0

4k² - 20k + 12k -60 = 0

4k ( k - 5 ) + 12 ( k - 5 ) = 0

( 4k + 12 )( k - 5 ) = 0

k = -3 , 5