Question

Find the value of k for which the roots of equation kx(3x-4)+4=0,are equal

Answer 1

kx*(3x-4)+4 = 0
3k$x^{2}$ - 4kx + 4 = 0;
Roots are equal : $b^{2}$ = 4ac

$(-4k)^{2}$ = 4*3k*4
k = 3

Answer 2

Answer:

The value of k is 3.

Step-by-step explanation:

The given equation is

$kx(3x-4)+4=0$

Where k can not be zero.

$3kx^2-4kx+4=0$

A quadratic equation $ax^2+bx+c=0$ has same roots if

$b^2-4ac=0$

Here a=3k, b=-4k, c=4

$(-4k)^2+-4(3k)(4)=0$

$16k^2-48k=0$

$16k(k-3)=0$

$k=0,3$

Therefore the value of k is 3.