Question

Find the value of k for which the roots of quadratic equation kx(x-2)+6=0 are equal

Answer 1

Answer:

kx^2 - 2kx +6

a=k , b= - 2k , c= 6

D=0 ( equal root's)

D = underroot b^2 -4ac

squaring both side

0^2 = k^2 -4 x -2k × 6

0. = k^2 - 48k

k^2 = 48k

k= 48

Answer 2

Answer:

Step-by-step explanation:

kx²-2kx+6=0

(-2k)²-4*6*k=0

4k²-24k=0

k²-6k=0

k(k-6)=0

k=6,0