Question

find the value of k for which the roots of quadratic equation kx²+2x+3=0 are real and equal.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$k = \frac{1}{3}$

Step-by-step explanation:

$k {x}^{2} + 2x + 3 = 0 \\ roots \: are \: real \: and \: equal \: . \\ therefore \: \: \\ ({2})^{2} - 4(k)(3) = 0 \\ = > 4 - 12k = 0 \\ = > k = \frac{4}{12} = \frac{1}{3} \\ = > k \: = \frac{1}{3}$

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@ aryanrathod51