Question

find the value of k for which the roots of the equation k x (3x -4)+4=0, are equal ​

Answer 1

Answer:

k = 3.

Step-by-step explanation:

assuming , equation to be ,

k*x*(3*x - 4) + 4 = 0 .

3*k*x*x - 4*k*x + 4 = 0;

for equal roots D = 0 . ax2 + bx + c = 0 ;

determinant =0 ==> b2 - 4ac = 0;

a = 3*k;

b = -4*k;

c = 4;

(4*k)^2 - 4*(3*k)*4 = 0;

16(k2 - 3k) = 0;

16 != 0 ; so k*k - 3*k = 0;

k(k-3) = 0;

k = 0 , k = 3 , but k = 0 , putting it in given equation will give 4 = 0 , not true , so k =  3 , will give us a quadratic equation ,