Question

Find the value of k for which the roots of the following equations are real and equal
k²x²- 2(2k-1)x+ 4 = 0​

Answer 1

Answer:

x

2

−2(2k−1)x+4=0

⇒ Here, a=k

2

,b=−2(2k−1),c=4

⇒ It is given that roots are real and equal.

∴ b

2

−4ac=0

⇒ [2(2k−1)]

2

−4(k

2

)(4)=0

⇒ 4(4k

2

−4k+1)−16k

2

=0

⇒ 16k

2

−16k+4−16k

2

=0

⇒ −16k=−4

∴ k=

4

1

Answer 2

Step-by-step explanation:

For real and equal roots, condition : b^2-4ac=0