Find the value of k for which the roots of the quadratic equation 2xsquare+kx+8=0, will have equal value.
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Answer:
k=8
Step-by-step explanation:
using discriminant,
a=2 b=k c=8
b^2-4ac=k^2-4×2×8
=k^2-64
for the roots to have a real value,
then b^2-4ac will be equal to 0
k^2-64=0
k^2=64
k=8
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