Question

Find the value of k for which the roots of the quadratic equation (k-4)x'2+3(k-4)x+2=0 are equal​

Answer 1

Answer:

Step-by-step explanation:

(k-4)x²+2(k-4)x+2=0

IF BOTH THE ROOTS ARE EQUAL;THEN DISCRIMINANT ⇒b²=4ac

then a=k-4; b=2(k-4) ;c=2; substituting the values

(2k-8)²=4×(k-4)×2

4k²+64-32k=8k-32

4k²-40k+96=0

k²-10k+24=0

(k-4)(k-6)=0

k=4,6