Question

Find the value of k for which the roots of the quadratic equationkx (x - 2) + 6 = 0 are equal.​

Answer 1

Step-by-step explanation:

the given equation can be written in the form of

k {x}^{2} - 2kx + 6 = 0kx2−2kx+6=0

now it has equal roots that means The Discriminant is 0

D = 0

Also

\begin{gathered}{b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6\end{gathered}b2−4ac=04k2−4(k)(6)=04k2−24k=04k(k−6)=0k−6=0k=6

Hence the value of K is 6.