Math, asked by ps589300220, 4 months ago

find the value of k for which the roots of the quadratic equation 5x2+(2k+1)x+k-2=0 are alpha,beeta satisfying the relation 2alpha +5beeta=1​

Answers

Answered by Anonymous
206

Step-by-step explanation:

ꜰɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ ᴋ ꜰᴏʀ ᴡʜɪᴄʜ ᴛʜᴇ ʀᴏᴏᴛꜱ ᴏꜰ ᴛʜᴇ Qᴜᴀᴅʀᴀᴛɪᴄ ᴇQᴜᴀᴛɪᴏɴ 5x2+(2ᴋ+1)x+ᴋ-2=0 ᴀʀᴇ ᴀʟᴘʜᴀ , ʙᴇᴇᴛᴀ ꜱᴀᴛɪꜱꜰʏɪɴɢ ᴛʜᴇ ʀᴇʟᴀᴛɪᴏɴ 2ᴀʟᴘʜᴀ+ 5 ʙᴇᴇᴛᴀ =1 .

Answered by vaishnavidumbare2004
4

Answer:

Thanks for Free point ❤️

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