Question

Find the value of k for which the roots of the quadratic equation (k-4)x2+2(k-4)x+2=0 are equal ?

Answer 1

Hope it will be helpful to you

Answer 2

Here is your answer:

We know that D= b² - 4ac
Also we are given that roots are equal that means D= 0
So, 0 = (2k-8)²- 4 (2k-8) (2)
0 = 4k²- 32k + 64 + (-8k + 32)2
0 = 4k²-32k + 64 +16k - 64
0 = 4k² - 16 k
0 = 4k (k-4)
0 = k-4
k =4
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