Question

find the value of k for which the sum of zero of the polynomial (k²–14)x²–2x–12 is 1​

Answer 1

Answer:

(k square - 14) 1 square - 2 x 1 - 12

k- 14 x 1 - 24 = 0

k -14 -24 = 0

k - 38 =0

k = 38 .

Answer 2

Answer:

Since the zero of polinomial is 1 substitute in

Since the zero of polinomial is 1 substitute in place of x.

Step-by-step explanation:

(k²-14)x²-2x-12

(k²-14)-2-12=0

k²-14-14=0

k²=28

k=√28

k=+5.29 or - 5.29

Hope it was useful!