Math, asked by wwwtmahindhra312, 11 months ago

find the value of k for which the system 3x+ky=7,2x-5y=1 will have infinitely many solutions.

Answers

Answered by laxmikumari231004
1

Answer:

Step-by-step explanation:

For infinite solutions

a1 /a2 = b1/b2 = c1/c2

3/2 = k/-5 = 7/1

k=-35

k=-15/2

Answered by Tiyagupta
3
3x+ky=7
a1=3,b1=k,c1=7

2x-5y=1
a2=2,b2=-5,c2=1

condition is given.
a1/a2=b1/b2=c1/c2

b1/b2=c1/c2
k/-5=7/1
k=-35
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