find the value of k for which the system 3x+ky=7,2x-5y=1 will have infinitely many solutions.
Answers
Answered by
1
Answer:
Step-by-step explanation:
For infinite solutions
a1 /a2 = b1/b2 = c1/c2
3/2 = k/-5 = 7/1
k=-35
k=-15/2
Answered by
3
3x+ky=7
a1=3,b1=k,c1=7
2x-5y=1
a2=2,b2=-5,c2=1
condition is given.
a1/a2=b1/b2=c1/c2
b1/b2=c1/c2
k/-5=7/1
k=-35
a1=3,b1=k,c1=7
2x-5y=1
a2=2,b2=-5,c2=1
condition is given.
a1/a2=b1/b2=c1/c2
b1/b2=c1/c2
k/-5=7/1
k=-35
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