Find the value of k for which the system has unique solution x-ky=2 and 3x+2y=5
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the answer is .........
given equation is ,
x-ky-2 ...............(1)
3x+2y-5=0..........(2)
so a1/a2=b1/b2
1/3=-k/2
2=-3k
k=-2/3
so k can be a any number to form unique solution except -2/3
given equation is ,
x-ky-2 ...............(1)
3x+2y-5=0..........(2)
so a1/a2=b1/b2
1/3=-k/2
2=-3k
k=-2/3
so k can be a any number to form unique solution except -2/3
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