Find the value of 'k' for which the system of equation 2x+3y=5 and 4x+ky =10 has infinite number of solution
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Answer:
2x+3y=5...................1)
4x+ky =10..................2)
in equation 1)
assuming x=1,y=1
2(1)+3(1)=5
2+3=5
putting the value of x and y in equation 2)
4(1)+k(1)=10
k=10-4
k=6
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