Question

Find the value of K for which the system of equation 2x + Y - 3 = 0 and 5 x + K Y + 7 = 0 has no solution ​

Answer 1

Answer:

this is done by me in my copy roughly

Answer 2

Answer:

Correct option is

D

2

x+y−4=0

2x+ky=3⇒2x+ky−3=0

a

1

x+b

1

y+c

1

=0

a

2

x+b

2

y+c

2

=0

For no solution

a

2

a

1

=

b

2

b

1



=

c

2

c

1

So,

2

1

=

k

1



=

−3

−4

2

1

=

k

1

∴k=2