Question

find the value of k for which the system of equation have infinity many solution x minus k y is equals to 2 and 3X + 6y is equals to minus 5

Answer 1

x - ky = 2
3x + 6y = -5

a1 = 1 b1 = -k c1 = 23

a2 = 3 b2 = 6 c2 = -5

For infinite solutions

a1/a2 = b1/b2 = c1/c2

1/3 = -k/6 = 23/-5

On taking. 1/3 = -k/6

-3k = 6

k = -2

Thanks

Answer 2

x-KY=2
3x+6y=-5
1/3=-k/6=2/-5
1/3=-k/6
cross multiple
-k=6/3
-k=2
k=-2