Question

Find the value of k for which the system of equation have a unique x-ky=2, 3x+2y=-5

Answer 1

a1 / a2 != b1 / b2
1 / 3 != -k / 2
k != -2/3

thus k have a unique value for every no. except -2/3

Answer 2

HELLO DEAR,


$the \: given \: equetion \: is \: \\ 3x + 2y = - 5 \\ x - ky = 2 \\ two \: given \: solution \: have \: unique \: solution \: if \\ \frac{ a_{1} }{ a_{2}} not \: equal \: to \frac{ b_{1}}{b_{2} } \\ = > \frac{3}{1} not \: equal \: to \: \frac{2}{ - k} \\ = > k \: not \: equal \: to \: - \frac{2}{3}$
So the given system of equations wiil have

unique solution for all values of k except -2/3

I HOPE ITS HELP YOU DEAR,
THANKS