Find the value of 'k' for which the system of equation kx+3y=1, 12x+ky=2 has no solution
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Kx+3y=1
12x+ky =2
in the case of no solution for equation
A1/A2=B1/B2
k/12=3/k
k^2=36
k=6
12x+ky =2
in the case of no solution for equation
A1/A2=B1/B2
k/12=3/k
k^2=36
k=6
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