Question

find the value of K for which the system of equations 2x-3y=7 and 8x+(k+4)y-28=0 has infinity many solutions
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Answer 1

Answer:

Step-by-step explanation:

a=2, b=-3,c=-7

A=8,B=k+4,C=-28

So for infinite results

a/A=b/B=c/C

2/8=-3/k+4=-7/-28

1/4=-3/k+4=1/4

-3/k+4=1/4

cross multiply

k+4=-12

k=-16