find the value of k for which the system of equations 2x+3y =7and 8x+(k+4)y-28=0
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firstly 2x+3y=7 (multiply by 4)
then 8x+12y=28
- 8x-(k+4)=-28
by ellimination method
12y-(k+4)y=0
y(12-k-4)=0 (y=0)
then k=8 ans
then 8x+12y=28
- 8x-(k+4)=-28
by ellimination method
12y-(k+4)y=0
y(12-k-4)=0 (y=0)
then k=8 ans
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