Question

find the value of k for which the system of equations has infinitely many solutions to (a)2x -3y=7;(k+2)x-(2k+1)y=3(2k-1) , (b)x+(k+1)y=5;(k+1)x+9y=8k-1



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Answer 1

Step-by-step explanation:

here a1/a2=b1/b2=c1/c2 so by b1/b2=c1/c2 we have -1/1-k=5/3k+1 which is -3k-1=5-k . 2k=-6 so k=-3

Answer 2

Answer:

Step-by-step explanation: