Question

Find the value of k for which the system of equations has a unique
solution
x-3y= -1
4x+ky= 4​

Answer 1

Answer:

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Step-by-step explanation:

$here, \: a1= 1 \: \: , b1 = -3, \: \: c1 = -1$

$and, \: a2 =4 , \: \: b2=k , \: c2 = 4$

$For \: unique \: solution :$

$\frac{a1}{a2} ≠ \frac{b1}{b2}$

$=> \frac{1}{4} = \frac{-3}{k}$

$=> k = 4×(-3) = -12$

$Therefore , \: the \: value \\ \: of \: k \: can \: be \: anything \: except \: 6 \: \\ for \: having \: unique \: solution.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$