Question

find the value of k for which the system of equations is kx+3y=k-3& 12x+ky=k will have no solution​

Answer 1

Answer:

kx+3y=k-3     12k + ky = k

, $\frac{k}{12} = \frac{3}{k} \neq \frac{-k+3}{-k} \\ k ^{2} =36 \\k = 6 , -6$

Answer 2

Answer:

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