Question

Find the value of k for which the system of equations kx +2 y= 5, 3x+y = 1 has unique

solution?​

Answer 1

Answer:

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Step-by-step explanation:

$here, \: a1= k \: \: , b1 = 2 , \: \: c1 = 5$

$and, \: a2 = 3 , \: \: b2=1 , \: c2 = 1$

$For \: unique \: solution :$

$\frac{a1}{a2} ≠ \frac{b1}{b2}$

$=> \frac{k}{3} = \frac{2}{1}$

$=> k = 2×3 = 6$

$Therefore , \: the \: value \\ \: of \: k \: should \: be \: 6 \: \\ for \: having \: unique \: solution.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

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