Math, asked by shobhitgahlaut43, 1 month ago

Find the value of k for which the system of equations kx +2 y= 5, 3x+y = 1 has unique

solution?​

Answers

Answered by ABHINAV012
2

Answer:

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Step-by-step explanation:

here, \:  a1= k  \:  \: , b1 = 2 , \:  \:  c1 = 5

and, \:  a2 = 3 ,   \: \: b2=1 ,  \: c2 = 1

For  \: unique \:  solution :

 \frac{a1}{a2}  ≠ \frac{b1}{b2}

=> \frac{k}{3} = \frac{2}{1}

=> k = 2×3 = 6

Therefore , \:  the \:  value  \\   \: of  \: k  \: should   \: be  \: 6 \:  \\  for \:  having  \: unique \:  solution.

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\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star

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