Question

find the value of k for which the system of equations kx minus y is equal to 2 ,6x minus 2 y is equal to 3 has no solution​

Answer 1

6x - 2y = 3.--i

(KX - y = 2)2 = 2kx -2 y =4.--ii

( 2kx -2 y =4) - (6x - 2y = 3)

2kx -2 y -6x +2y = 4-3

2kx -6x = 1

k - 3 = 1

k =4